Bankroll calculator
What a percentage unit actually commits: the stake per bet, the cost of a losing run, and how many consecutive losses the bankroll survives.
Bankroll and rule
Percentages go in as numbers: 2 means 2% of the bankroll per bet. The losing streak is a count of bets, so whole numbers only — it is the bad run you want to survive, not a prediction.
What the rule costs
At or under 5% per unit the run you declared leaves the bankroll still working. A run of ten reaches 38.54% of bettors inside 1,000 bets at even money, so a plan that only holds if you never meet one is not a plan.
The unit percentage is not a preference. It is your decision about how long the worst losing run is allowed to be before you are out of the game.
The rule that decides how long a bad run you survive
A unit is a percentage of the bankroll, not an amount, and the difference only shows up when things go wrong. Stake a fixed 40 forever and a bankroll that has fallen to 1,000 is betting 4% instead of 2%: the rule tightens exactly when it should loosen. Recalculate the unit against the current balance and every loss makes the next stake smaller, which is what stops a bad run from finishing the job. The asymmetry underneath is the whole reason to care — losing 20% needs +25.00% to recover, losing 50% needs +100.00%, and losing 80% needs +400.00%. Nothing in the second half of those pairs is symmetric with the first, and no edge is big enough to make a 400.00% recovery a plan rather than a hope. A 2,000 bankroll at 2% stakes 40 a bet, absorbs ten straight losses for 400.00, and comes out down 20.00% — having used ten of the 50 consecutive losses that stake could survive.
A run of ten losses at prices around 2.00 is ordinary, not bad luck, and this is the number that makes the point. At even money any single sequence of ten has a probability of 0.098% — one in 1,024 — which reads like never until you count how many sequences a season contains. Across 1,000 bets the chance of meeting at least one losing run of ten or longer is 38.54%; at 2.10, where a bettor with no edge wins 47.62% of the time, it is 52.31% — better than a coin flip. Over 500 bets the same two figures are 21.45% and 30.73%, and the longest run to expect in 1,000 even-money bets is about ten, because it grows with the base-two logarithm of the number of bets. The run is not the tail of the distribution, it is the middle of it, so a unit above 5% is a bet on not meeting the ordinary case: at 5% those ten losses take half the bankroll, at 10% they take all of it. When the edge is measured rather than assumed, the Kelly criterion calculator sizes the unit from the edge itself — read what it gives you as a ceiling, and this page as the floor beneath it.
A 2,000 bankroll at 2% per bet
- Bankroll
- 2,000
- Unit size
- 2%
- Stake per bet
- 40.00
- Ten losses in a row
- 400.00
- Drawdown
- 20.00%
- Losses to ruin
- 50
That 20.00% hole needs a +25.00% gain on what is left to get back to 2,000. Move the unit to 5% and the same ten losses cost 1,000 — a 50.00% drawdown needing +100.00% to recover, with the bankroll covering 20 consecutive losses instead of 50. Three points on the rule, and the run you survive is less than half as long.
Questions
What unit size should I use?
One to two percent of the bankroll per bet is the usual range for flat staking, and above five percent the ordinary losing run becomes an account-ending event. The honest way to pick is backwards: choose the losing run you intend to survive, then read the drawdown this calculator gives and ask whether you would keep betting the same way after it.
Why does losses to ruin show a whole number?
Because it counts bets, and a fraction of a bet is not one. A 1,000 bankroll at 3% gives a 30 unit, which is 33 losses and a third — so the answer is 33, rounded down, because the bankroll cannot cover the next one in full. Rounding up would promise a bet the money does not exist for.
Is a ten-bet losing run really normal?
Yes, and the arithmetic is not close. Any one sequence of ten losses at even money is a 0.098% event, but across 1,000 bets there are enough sequences that the chance of meeting at least one is 38.54%, rising to 52.31% at 2.10 where a bettor with no edge wins 47.62% of the time. Plan around it rather than being surprised by it.
Should I use this or the Kelly criterion?
Use this when you do not have a measured edge, which is most of the time: a percentage unit needs no probability estimate and its worst case is knowable in advance. The Kelly criterion calculator is the right tool once you can defend a probability, and it will usually recommend more than a flat 2%. Treating its answer as a ceiling and a flat rule as the floor keeps both honest.
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